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Final Temperature Of Mixture Calculator

Final Temperature Equation:

\[ T_{final} = \frac{m_1 c_1 T_1 + m_2 c_2 T_2}{m_1 c_1 + m_2 c_2} \]

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1. What is the Final Temperature of Mixture Equation?

The final temperature equation calculates the equilibrium temperature when two substances at different temperatures are mixed together. It's based on the principle of conservation of energy, where heat lost by the hotter substance equals heat gained by the cooler substance.

2. How Does the Calculator Work?

The calculator uses the final temperature equation:

\[ T_{final} = \frac{m_1 c_1 T_1 + m_2 c_2 T_2}{m_1 c_1 + m_2 c_2} \]

Where:

Explanation: The equation calculates the weighted average of temperatures based on the heat capacities of the two substances.

3. Importance of Final Temperature Calculation

Details: Calculating the final temperature of mixtures is crucial in thermodynamics, chemical engineering, cooking, and various industrial processes where temperature control is important.

4. Using the Calculator

Tips: Enter all values in the specified units. Masses should be in grams, specific heat capacities in J/gK, and temperatures in Kelvin. All values must be positive numbers.

5. Frequently Asked Questions (FAQ)

Q1: What if the substances have the same specific heat capacity?
A: If c₁ = c₂, the equation simplifies to T_final = (m₁T₁ + m₂T₂)/(m₁ + m₂), which is a mass-weighted average.

Q2: Can this calculator be used for more than two substances?
A: No, this calculator is specifically designed for two substances. For more substances, the equation would need to be extended.

Q3: What assumptions does this calculation make?
A: It assumes no heat loss to the surroundings, no phase changes occur, and the specific heat capacities remain constant.

Q4: Can I use Celsius instead of Kelvin?
A: Yes, because the equation uses temperature differences, both Celsius and Kelvin will give the same result as long as all temperatures use the same scale.

Q5: What if one substance is much hotter than the other?
A: The calculator will still work correctly. The final temperature will be closer to the temperature of the substance with the larger heat capacity (m×c).

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